document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=83958>Question 83958</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve algebraically using only one variable. The perimeter, which is the sum of all sides, of a rectangle is 48 square inches. The length of the rectangle is three more than twice its width. Find the length and width of the rectangle </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #60402 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=60402\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2w+2(2w+3)=48<BR>\n" );
document.write( "2w+4w+6=48<BR>\n" );
document.write( "6w=48-6<BR>\n" );
document.write( "6w=42<BR>\n" );
document.write( "w=42/6<BR>\n" );
document.write( "w=7 answer for the width.<BR>\n" );
document.write( "length=2w+3, 2*7+3, 14+3, 17 for the length.<BR>\n" );
document.write( "proof<BR>\n" );
document.write( "2*7+2*17=48<BR>\n" );
document.write( "14+34=48<BR>\n" );
document.write( "48=48   </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );