document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=83959>Question 83959</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A student has grades of 89, 96, 88 and 90 on the first four exams in a certain course. What is the lowest(whole number) grade that must be obtained on the fifth exam in order for this student to have an average of more than 92?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #60400 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=60400\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (89+96+88+90+x)/5=92<BR>\n" );
document.write( "(363+x)/5=92 now cross multiply<BR>\n" );
document.write( "363+x=460<BR>\n" );
document.write( "x=460-363<BR>\n" );
document.write( "x=97 for the required final test to have an acerage iof 92.<BR>\n" );
document.write( "proof<BR>\n" );
document.write( "(89+96+88+90+97)/5=92<BR>\n" );
document.write( "460/5=92<BR>\n" );
document.write( "92=92\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );