document.write( "Question 983113: A one-plane airline has a passenger capacity of 120. The number of passengers on a flight is normally distributed with a mean of 90 and a standard deviation of 15.
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document.write( "1. What is the probability that a flight will be “overbooked” (ie not able to get a seat on the flight)? \r
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document.write( "2. If there are 5 flights a day, every day, how many flights will be overbooked in a 30 day month?\r
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document.write( "Please help! and explain! Thanks so much! \n" );
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Algebra.Com's Answer #603929 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! # 1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "X = number of tickets sold\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "\"Overbooked\" means that more than 120 tickets have been sold. \n" ); document.write( "So when X > 120, the flight has been overbooked. \n" ); document.write( "We want to find the probability P(X > 120)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let x = 120. Find the z-score \n" ); document.write( "z = (x-mu)/sigma \n" ); document.write( "z = (120-90)/15 \n" ); document.write( "z = 30/15 \n" ); document.write( "z = 2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Use this z-score to find the value of P(Z < 2). I'm going to use a table, but you can use a TI calculator. The normalcdf function gets the job done.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "I used a table to find that P(Z < 2) = 0.97725\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So,\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "P(Z > 2) = 1 - P(Z < 2) \n" ); document.write( "P(Z > 2) = 1 - 0.97725 \n" ); document.write( "P(Z > 2) = 0.02275\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Therefore, \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "P(X > 120) = P(Z > 2) \n" ); document.write( "P(X > 120) = 0.02275\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The probability of overbooking is 0.02275 \n" ); document.write( "There's a 2.275% chance that the flight is overbooked.\r \n" ); document.write( "\n" ); document.write( "==============================================================\r \n" ); document.write( "\n" ); document.write( "# 2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Multiply the probability with the number of flights per day.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "0.02275*5 = 0.11375\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So on average, we expect 0.11375 flights per day to be overbooked. On any given day, this is a good thing since the number is small. If we extend this over 30 days, then 30*0.11375 = 3.4125\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So over 30 days, we expect on average roughly 3.4125 flights to be overbooked. \n" ); document.write( " |