document.write( "Question 983071: Solve the system of equations\r
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Algebra.Com's Answer #603917 by Edwin McCravy(20054)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "\"system%28x%5E2+%2B+y%5E2+-+x+-+y+=+18%2C%0D%0Axy+%2B+2x+%2B+2y+=+26%29\"\r\n" );
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document.write( "Instead of doing your problem for you, I will do one exactly \r\n" );
document.write( "in every detail step-by-step like your problem.  All you have\r\n" );
document.write( "to do is use the problem below as a model. The problem I will\r\n" );
document.write( "do is:\r\n" );
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document.write( "\"x%5E2+%2B+y%5E2+-+3x+-+3y+=+8%2C++%0D%0Axy+%2B+2x+%2B+2y+=+24%29\"\r\n" );
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document.write( "One thing we observe about this problem is that it is symmetrical\r\n" );
document.write( "in x and y.  That is we have the same two equations if we interchange\r\n" );
document.write( "x and y.  Therefore any time we get a pair of solutions for x, one will\r\n" );
document.write( "be a solution for x and the other will be a solution for y.\r\n" );
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document.write( "Solve the second for y\r\n" );
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document.write( "\"xy+%2B+2x+%2B+2y+=+24\"\r\n" );
document.write( "\"xy%2B2y=24-2x\"\r\n" );
document.write( "\"y%28x%2B2%29=24-2x\"\r\n" );
document.write( "\"y+=+%2824-2x%29%2F%28x%2B2%29\" \r\n" );
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document.write( "Substitute in the first equation:\r\n" );
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document.write( "\"x%5E2+%2B+%28%2824-2x%29%2F%28x%2B2%29%29%5E2+-+3x+-+3%28%2824-2x%29%2F%28x%2B2%29%29+=+8\"\r\n" );
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document.write( "Multiply through by (x+2)², [but we know x can't be -2]\r\n" );
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document.write( "Get binomials in descending order:\r\n" );
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document.write( "\"x%5E4%2Bx%5E3-6x%5E2-200x%2B400+=+0\"\r\n" );
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document.write( "Looking at the graph on a graphing calculator it appears that \r\n" );
document.write( "it has solutions 2 and 5 but it probably has a pair of conjugate\r\n" );
document.write( "complex solutions too.  We use synthetic division with x=2\r\n" );
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document.write( "2 | 1 1 -6 -200  400\r\n" );
document.write( "  |   2  6    0 -400 \r\n" );
document.write( "    1 3  0 -200    0\r\n" );
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document.write( "5 | 1  3   0 -200\r\n" );
document.write( "  |    5  40  200    \r\n" );
document.write( "    1  8  40    0\r\n" );
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document.write( "So we have factored the polynomial as\r\n" );
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document.write( "\"%28x-2%29%28x-5%29%28x%5E2%2B8x%2B40%29+=+0\"\r\n" );
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document.write( "So we have solutions x=2, x=5, \r\n" );
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document.write( "By the symmetry, we know that when x=2, y=5\r\n" );
document.write( "and when x=5, y=2.\r\n" );
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document.write( "we get the other solutions from\r\n" );
document.write( "using the quadratic formula, since it won't factor.\r\n" );
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document.write( "\"x+=+%28-8+%2B-+sqrt%2864-160+%29%29%2F2+\"\r\n" );
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document.write( "\"x+=+%28-8+%2B-+sqrt%28-96+%29%29%2F2+\"\r\n" );
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document.write( "\"x+=+%28-8+%2B-+i%2Asqrt%2896+%29%29%2F2+\"\r\n" );
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document.write( "\"x+=+%28-8+%2B-+i%2Asqrt%2816%2A6+%29%29%2F2+\"\r\n" );
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document.write( "\"x+=+%28-8+%2B-+4i%2Asqrt%286%29%29%2F2+\"\r\n" );
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document.write( "\"x+=+%282%28-4+%2B-+i%2Asqrt%286%29%29%29%2F2+\"\r\n" );
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document.write( "\"x+=+-4+%2B-+i%2Asqrt%286%29+\"\r\n" );
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document.write( "So the other pair of solutions, by symmetry, are\r\n" );
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document.write( "if \"x+=+-4+%2B+i%2Asqrt%286%29+\", then \"y+=+-4+-+i%2Asqrt%286%29+\"\r\n" );
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document.write( "and \r\n" );
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document.write( "if \"x+=+-4+-+i%2Asqrt%286%29+\", then \"y+=+-4+%2B+i%2Asqrt%286%29+\"\r\n" );
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document.write( "Now you do your problem exactly step-by step like I did this one.\r\n" );
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document.write( "Edwin
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