document.write( "Question 983082: Hi I have searched for an eqjuation similar to the one I need to solve. Can you please help me?\r
\n" ); document.write( "\n" ); document.write( "e^0.4x = 4^x-2
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Algebra.Com's Answer #603885 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "\"e%5E%280.4x%29+=+4%5E%28x-2%29\"\r
\n" ); document.write( "\n" ); document.write( "\"e%5E%280.4x%29+=+%282%5E2%29%5E%28x-2%29\"\r
\n" ); document.write( "\n" ); document.write( "\"e%5E0.4x+=+2%5E%282x-4%29\"\r
\n" ); document.write( "\n" ); document.write( "\"log%28e%5E%280.4x%29%29+=+log%282%5E%282x-4%29%29\"\r
\n" ); document.write( "\n" ); document.write( "\"%280.4x%29log%28e%29+=+%282x-4%29log%282%29\"....since \"log%28e%29=1\", we have\r
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\n" ); document.write( "\n" ); document.write( "\"0.4x=%282x-4%29log%282%29\"\r
\n" ); document.write( "\n" ); document.write( "\"0.4x+=+2x%2Alog%282%29-4log%282%29\"\r
\n" ); document.write( "\n" ); document.write( "\"4log%282%29+=+2x%2Alog%282%29-+0.4x\"\r
\n" ); document.write( "\n" ); document.write( "\"4log%282%29+=+2x%28log%282%29-+0.2%29\"\r
\n" ); document.write( "\n" ); document.write( "\"2log%282%29+=+x%28log%282%29-+0.2%29\"\r
\n" ); document.write( "\n" ); document.write( "\"x=2log%282%29%2F%28log%282%29-+0.2%29\"\r
\n" ); document.write( "\n" ); document.write( "\"x=2.81112\"\r
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