document.write( "Question 83831: A plane travels from city A to city B and it takes two hours...on the second trip the plane travels from city A to City B and it flys 10mph slower and it takes 2 1/2 hours...what is the distance from city A to city B? \n" ); document.write( "
Algebra.Com's Answer #60388 by ptaylor(2198)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Let d=distance from city A to city B \n" ); document.write( "r=rate on first trip \n" ); document.write( "(r-10)=rate on second trip\r \n" ); document.write( "\n" ); document.write( "distance(d) equals rate(r) times time(t) or d=rt; r=d/t and t=d/r\r \n" ); document.write( "\n" ); document.write( "First trip:\r \n" ); document.write( "\n" ); document.write( "d=rt=r(2) or \n" ); document.write( "d=2r\r \n" ); document.write( "\n" ); document.write( "Second trip:\r \n" ); document.write( "\n" ); document.write( "d=(r-10)(2.5)\r \n" ); document.write( "\n" ); document.write( "Since the distance travelled on the first and second trip is the same, we have:\r \n" ); document.write( "\n" ); document.write( "2r=(r-10)(2.5) get rid of parens\r \n" ); document.write( "\n" ); document.write( "2r=2.5r-25 subtract 2.5r from both sides \n" ); document.write( "2r-2.5r=2.5r-2.5r-25 collect like terms\r \n" ); document.write( "\n" ); document.write( "-0.5r=-25 divide both sides by -0.5\r \n" ); document.write( "\n" ); document.write( "r=50 mph but we know that:\r \n" ); document.write( "\n" ); document.write( "d=2r or d=2*50=100 mi------------distance between city A and City B\r \n" ); document.write( "\n" ); document.write( "CK\r \n" ); document.write( "\n" ); document.write( "First trip:\r \n" ); document.write( "\n" ); document.write( "2*50=100 \n" ); document.write( "100=100 \n" ); document.write( "and \n" ); document.write( "(2.5)(40)=100 \n" ); document.write( "100=100\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hope this helps-----ptaylor \n" ); document.write( " \n" ); document.write( " |