document.write( "Question 83900This question is from textbook Algebra and Trigonometry
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\n" ); document.write( "\n" ); document.write( "(x-3)^2/25 + (y-4)^2/16 =1
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Algebra.Com's Answer #60387 by chitra(359)\"\" \"About 
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The given equation is: \"%28%28x-3%29%5E2%2F25%29+%2B+%28%28y-4%29%5E2%2F16%29+=+1\" \r
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\n" ); document.write( "\n" ); document.write( "Comparing this to the standard equation, we get: \r
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\n" ); document.write( "\n" ); document.write( "\"%28%28x+-+h%29%5E2%2Fa%5E2%29+%2B+%28%28y+-+k%29%5E2%2Fb%5E2%29+=+1\" \r
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\n" ); document.write( "\n" ); document.write( "We find that the centre of the ellipse given by (h,k) is equal to (3, 4) \r
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\n" ); document.write( "\n" ); document.write( "The foci of the Ellipse is given by (+- ae, 0) \r
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\n" ); document.write( "\n" ); document.write( "So we first find the eccentricity using the formula: \r
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\n" ); document.write( "\n" ); document.write( "e = \"+sqrt%281+-+%28b%5E2%2Fa%5E2%29%29+\" \r
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\n" ); document.write( "\n" ); document.write( "e = \"+sqrt%281+-+16%2F25%29%29+\" \r
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\n" ); document.write( "\n" ); document.write( "e = 3/5 \r
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\n" ); document.write( "\n" ); document.write( "So now focus is: (+- ae, 0) = (+ -3, 0) \r
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\n" ); document.write( "\n" ); document.write( "Now the vertex is (+ - a, 0) = (+- 5, 0) \r
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\n" ); document.write( "\n" ); document.write( "hence, the solution
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