document.write( "Question 983070: I am trying to solve (1/8)^(2x-3) = 16^(x+1) \n" ); document.write( "
Algebra.Com's Answer #603867 by ikleyn(52813)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "Is this the equation you need to solve?\r
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\n" ); document.write( "\n" ); document.write( "\"%281%2F8%29%5E%282x-3%29\" = \"16%5E%28x%2B1%29\".\r
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\n" ); document.write( "\n" ); document.write( "If so,  then let us write it in terms of degrees of  2:\r
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\n" ); document.write( "\n" ); document.write( "\"2%5E%28-3%2A%282x-3%29%29\" = \"2%5E%284%2A%28x%2B1%29%29\".\r
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\n" ); document.write( "\n" ); document.write( "It gives\r
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\n" ); document.write( "\n" ); document.write( "-3*(2x-3) = 4*(x+1).\r
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\n" ); document.write( "\n" ); document.write( "To solve the last equation,  simplify it step by step:\r
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\n" ); document.write( "\n" ); document.write( "-6x + 9 = 4x + 4,\r
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\n" ); document.write( "\n" ); document.write( "-6x - 4x = 4 - 9,\r
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\n" ); document.write( "\n" ); document.write( "-10x = -5,\r
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\n" ); document.write( "\n" ); document.write( "x = \"%28-5%29%2F%28-10%29\" = \"1%2F2\".\r
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\n" ); document.write( "\n" ); document.write( "Check.  The left side of the original equation at  x = \"1%2F2\"  is  \"%281%2F8%29%5E%281-3%29\" = \"%281%2F8%29%5E%28-2%29\" = \"8%5E2\" = \"64\".\r
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\n" ); document.write( "\n" ); document.write( "            The right side of the original equation at  x = \"1%2F2\"  is  \"16%5E%283%2F2%29\" = \"4%5E3\" = 64. \r
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\n" ); document.write( "\n" ); document.write( "Answer.  x = \"1%2F2\".\r
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