document.write( "Question 983070: I am trying to solve (1/8)^(2x-3) = 16^(x+1) \n" ); document.write( "
Algebra.Com's Answer #603866 by Edwin McCravy(20059)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "I won't do your problem for you.  Instead here is one EXACTLY like yours.\r\n" );
document.write( "Use it as a model to solve yours:\r\n" );
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document.write( "\"%281%2F27%29%5E%283x-4%29=9%5E%28x-5%29\"\r\n" );
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document.write( "Write 27 as 3³ and 9 as (3²)\r\n" );
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document.write( "\"%281%2F3%5E3%29%5E%283x-4%29=%283%5E2%29%5E%28x-5%29\"\r\n" );
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document.write( "Write \"1%2F3%5E3\" as \"3%5E%28-3%29\"\r\n" );
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document.write( "\"%283%5E%28-3%29%29%5E%283x-4%29=%283%5E2%29%5E%28x-5%29\"\r\n" );
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document.write( "remove the parentheses by multiplying the exponents:\r\n" );
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document.write( "\"3%5E%28-9x%2B12%29=3%5E%282x-10%29\"\r\n" );
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document.write( "Since the bases are the same, and they are positive\r\n" );
document.write( "and not equal to 1, we may equate the exponents only\r\n" );
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document.write( "\"-9x%2B12=2x-10\"\r\n" );
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document.write( "\"-9x%2B12=2x-10\"\r\n" );
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document.write( "\"-11x=-22\"\r\n" );
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document.write( "\"x=2\"\r\n" );
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document.write( "Edwin

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