document.write( "Question 983057: Pls help solve below two questions:\r
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document.write( "Question No. 1
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document.write( "x/3 - y/4 = 2x - y +12\r
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document.write( "Question No. 2
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document.write( "A Company manufactures two different products, A and B. Each unit of product A costs $6 to produce and each unit of product B costs $4. The Company insists that total costs for the two products be $500.
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document.write( "(a) Define the cost equation which states that the total cost of producing x units of product A and y units of product B equals $500
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document.write( "(b) Assuming the Company has agreed to fill an order for 50 units of product A, how many units of product B should be produced if total costs are to be kept at $500? \n" );
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Algebra.Com's Answer #603859 by rothauserc(4718)![]() ![]() You can put this solution on YOUR website! 1) x/3 - y/4 = 2x - y +12 \n" ); document.write( "multiply both sides of = by 12 \n" ); document.write( "4x - 3y = 24x - 12y + 144 \n" ); document.write( "9y = 20x + 144 \n" ); document.write( "y = (20x/9) + 16 \n" ); document.write( "this is a line, here is its graph. note that each point(x,y) on the line is a solution, for example (0, 16) is a solution \n" ); document.write( "here is its graph \n" ); document.write( " \n" ); document.write( "****************************************************************************** \n" ); document.write( "2) let x be the number of product A items and y be the number of product B items, then \n" ); document.write( "a) 6x + 4y = 500 \n" ); document.write( "b) (6*50) + 4y = 500 \n" ); document.write( "300 + 4y = 500 \n" ); document.write( "4y = 200 \n" ); document.write( "y = 50, therefore \n" ); document.write( "50 units of product B should be produced \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |