document.write( "Question 982979: Please help solve. Solve the system of 2 equations and 2 unknowns using the echelon method.\r
\n" ); document.write( "\n" ); document.write( "x/4 + y/4 = 1\r
\n" ); document.write( "\n" ); document.write( "x/5 = y/5 = 12/5\r
\n" ); document.write( "\n" ); document.write( "Your help would be appreciated. The question on paper is x is the top number 4 is the bottom number, etc. I did not know how to type the problem in fraction form. Thank you.
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Algebra.Com's Answer #603767 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
\"x%2F4+%2B+y%2F4+=+1\"
\n" ); document.write( "\"x%2F5+-+y%2F5+=+12%2F5\"
\n" ); document.write( "First step, get rid of the fractions.
\n" ); document.write( "Multiply each row by the denominator in the row.
\n" ); document.write( "1.\"x%2By=4\"
\n" ); document.write( "2.\"x-y=12\"
\n" ); document.write( "Replace the second row by multiplying the previous second row by (-1) and adding to the first row.
\n" ); document.write( "\"x%2By-x%2By=4-12\"
\n" ); document.write( "\"2y=-8\"
\n" ); document.write( "3.\"y=-4\"
\n" ); document.write( "So that leaves you with
\n" ); document.write( "1.\"x%2By=4\"
\n" ); document.write( "2.\"y=-4\"
\n" ); document.write( "Substituting,
\n" ); document.write( "\"x-4=4\"
\n" ); document.write( "\"x=8\"\r
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