document.write( "Question 982906: a bricklayer measured the length of his wall to be 4.10m, if the actual length is 4.25m, what is his percentage error \n" ); document.write( "
Algebra.Com's Answer #603733 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
Error=((Actual-Measured)/Actual)*100\r
\n" ); document.write( "\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( "\"E=%28%284.25-4.1%29%2F4.25%29%2A100=3.5\"
\n" ); document.write( "3.5%
\n" ); document.write( "
\n" ); document.write( "
\n" );