document.write( "Question 982911: A chemist has three different acid solutions. The first acid solution contains 25% acid, the second contains 40% and the third contains 80%. He wants to use all three solutions to obtain a mixture of 66 liters containing 55% acid, using 3 times as much of the 80% solution as the 40% solution. How many liters of each solution should be used?\r
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Algebra.Com's Answer #603710 by josgarithmetic(39618)\"\" \"About 
You can put this solution on YOUR website!
TYPE__________PERCENT-CONC_______VARIABLE
\n" ); document.write( "Low____________25_________________x
\n" ); document.write( "Medium_________40_________________y
\n" ); document.write( "High___________80_________________z
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\n" ); document.write( "DESCRIPTION: \"z%2Fy=3\"
\n" ); document.write( "WANT: 66 liters of 55%\r
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\n" ); document.write( "\n" ); document.write( "Accounting for volumes
\n" ); document.write( "\"x%2By%2Bz=66\"
\n" ); document.write( "\"x%2By%2B3y=66\"
\n" ); document.write( "\"x%2B4y=66\"\r
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\n" ); document.write( "\n" ); document.write( "Account for concentrations keeping all as percents
\n" ); document.write( "\"%2825x%2B40y%2B80z%29%2F%2866%29=55\"\r
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\n" ); document.write( "\n" ); document.write( "z can be eliminated from this, just as done in volume account.
\n" ); document.write( "\"%2825x%2B40y%2B80%2A3y%29%2F66=55\"
\n" ); document.write( "Divide members by 5.
\n" ); document.write( "\"%285x%2B9y%2B16%2A3y%29%2F66=11\"
\n" ); document.write( "\"highlight_green%28%285x%2B57y%29%2F66=11%29\"
\n" ); document.write( "\"5x%2B57y=726\"\r
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\n" ); document.write( "\n" ); document.write( "A system of two equations in just x and y is possible.
\n" ); document.write( "\"system%28highlight%28x%2B4y=66%29%2Chighlight%285x%2B57y=726%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "Solve for x and y any way you want or know.\r
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\n" ); document.write( "\n" ); document.write( "Equivalent:
\n" ); document.write( "\"system%285x%2B20y=330%2C5x%2B57y=726%29\"
\n" ); document.write( "subtract first equation from second equation to find y.
\n" ); document.write( "\"highlight%28y=10.702%2Aliters%29\"-------the 40% material\r
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\n" ); document.write( "\n" ); document.write( "Before even finding x, finding z is possible right now.
\n" ); document.write( "\"z=3%2Ay\"
\n" ); document.write( "\"z=3%2A10.702\"
\n" ); document.write( "\"highlight%28z=32.108%2Aliters%29\"------the 80% material\r
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\n" ); document.write( "\n" ); document.write( "The original volume sum equation most easily will give x.\r
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