document.write( "Question 982911: A chemist has three different acid solutions. The first acid solution contains 25% acid, the second contains 40% and the third contains 80%. He wants to use all three solutions to obtain a mixture of 66 liters containing 55% acid, using 3 times as much of the 80% solution as the 40% solution. How many liters of each solution should be used?\r
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Algebra.Com's Answer #603710 by josgarithmetic(39618)![]() ![]() ![]() You can put this solution on YOUR website! TYPE__________PERCENT-CONC_______VARIABLE \n" ); document.write( "Low____________25_________________x \n" ); document.write( "Medium_________40_________________y \n" ); document.write( "High___________80_________________z \n" ); document.write( "- \n" ); document.write( "DESCRIPTION: \n" ); document.write( "WANT: 66 liters of 55%\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Accounting for volumes \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Account for concentrations keeping all as percents \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "z can be eliminated from this, just as done in volume account. \n" ); document.write( " \n" ); document.write( "Divide members by 5. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "A system of two equations in just x and y is possible. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Solve for x and y any way you want or know.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Equivalent: \n" ); document.write( " \n" ); document.write( "subtract first equation from second equation to find y. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Before even finding x, finding z is possible right now. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The original volume sum equation most easily will give x.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |