document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=982865>Question 982865</A>: <I><SPAN STYLE=\"word-break: break-all;\"> X^2+(x+6)^2=(x+12)^2<BR>\n" );
document.write( "I got the answer with trial an error. But i don't understand how to show the work.<BR>\n" );
document.write( "(Finding the lengths of all legs of a right triangle) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #603649 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=603649\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> X^2+(x+6)^2=(x+12)^2<BR>\n" );
document.write( "I got the answer with trial an error. But i don't understand how to show the work.<BR>\n" );
document.write( "(Finding the lengths of all legs of a right triangle)<BR>\n" );
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document.write( "X^2+(x+6)^2=(x+12)^2<BR>\n" );
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document.write( "x^2 + x^2 + 12x + 36 = x^2 + 24x + 144<BR>\n" );
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document.write( "x^2 - 12x - 108 = 0<BR>\n" );
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document.write( "(x-18)(x+6) = 0<BR>\n" );
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document.write( "Positive solution::<BR>\n" );
document.write( "x = 18<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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