document.write( "Question 981245: Given that ABCD is a straight line. B is the midpoint of AC and C is the midpoint of BD. If coordinates A and D are (-14,2) and (-2, 2) respectively. Find the coordinates of A and C. \n" ); document.write( "
Algebra.Com's Answer #603592 by Fombitz(32388)\"\" \"About 
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From the midpoint formula,
\n" ); document.write( "\"x%5BB%5D=%28x%5BA%5D%2Bx%5BC%5D%29%2F2\"
\n" ); document.write( "\"y%5BB%5D=%28y%5BA%5D%2By%5BC%5D%29%2F2\"
\n" ); document.write( "and
\n" ); document.write( "\"x%5BC%5D=%28x%5BB%5D%2Bx%5BD%5D%29%2F2\"
\n" ); document.write( "\"y%5BC%5D=%28y%5BB%5D%2By%5BD%5D%29%2F2\"
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( "1.\"2x%5BB%5D=-14%2Bx%5BC%5D\"
\n" ); document.write( "2.\"2y%5BB%5D=2%2By%5BC%5D\"
\n" ); document.write( "and
\n" ); document.write( "3.\"2x%5BC%5D=x%5BB%5D-2\"
\n" ); document.write( "4.\"2y%5BC%5D=y%5BB%5D%2B2\"
\n" ); document.write( "So solving the x equations (1 & 3) by substituting,
\n" ); document.write( "\"2%282x%5BB%5D%2B14%29=x%5BB%5D-2\"
\n" ); document.write( "\"4x%5BB%5D%2B28=x%5BB%5D-2\"
\n" ); document.write( "\"3x%5BB%5D=-30\"
\n" ); document.write( "\"x%5BB%5D=-10\"
\n" ); document.write( "and
\n" ); document.write( "\"2%28-10%29=-14%2Bx%5BC%5D\"
\n" ); document.write( "\"-20=-14%2Bx%5BC%5D%7D%7D%0D%0A%7B%7B%7Bx%5BC%5D=-6\"
\n" ); document.write( "Then solving the y equations (2 & 4) similarly,
\n" ); document.write( "\"2%282y%5BC%5D-2%29=2%2By%5BC%5D\"
\n" ); document.write( "\"4y%5BC%5D-4=2%2By%5BC%5D\"
\n" ); document.write( "\"3y%5BC%5D=6\"
\n" ); document.write( "\"y%5BC%5D=2\"
\n" ); document.write( "and
\n" ); document.write( "\"2%282%29=y%5BB%5D%2B2\"
\n" ); document.write( "\"y%5BB%5D=2\"
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\n" ); document.write( ".\r
\n" ); document.write( "\n" ); document.write( "B:(-10,2)
\n" ); document.write( "C:(-6,2)
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