document.write( "Question 982757: If a man is 5 times older than his son, 4 years ago the product of their ages was 52, Now tell their present ages? ( Man? Son?)
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Algebra.Com's Answer #603573 by macston(5194)\"\" \"About 
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\n" ); document.write( "M=man; S=son
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\n" ); document.write( "M=5S
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\n" ); document.write( "(M-4yrs)(S-4yrs)=52yrs
\n" ); document.write( "(5S-4yrs)(S-4yrs)=52yrs
\n" ); document.write( "5S^2-24S+16=52
\n" ); document.write( "5S^2-24S-36=0
\n" ); document.write( "(5S+6)(S-6)=0
\n" ); document.write( "5S+6=0 or S-6=0
\n" ); document.write( "5S=-6 or S=6
\n" ); document.write( "S=-5/6 or S=6
\n" ); document.write( "ANSWER 1: Son is 6 years old
\n" ); document.write( "M=5(S)=5(6yrs)=30 years old
\n" ); document.write( "ANSWER 2: The man is 30 years old.
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\n" ); document.write( "CHECK:
\n" ); document.write( "(M-4yrs)(S-4yrs)=52yrs
\n" ); document.write( "(30yrs-4yrs)(6yrs-4yrs)=52yrs
\n" ); document.write( "(26yrs)(2yrs)=52yrs
\n" ); document.write( "52yrs=52yrs
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