document.write( "Question 982757: If a man is 5 times older than his son, 4 years ago the product of their ages was 52, Now tell their present ages? ( Man? Son?)
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Algebra.Com's Answer #603573 by macston(5194)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "M=man; S=son \n" ); document.write( ". \n" ); document.write( "M=5S \n" ); document.write( ". \n" ); document.write( "(M-4yrs)(S-4yrs)=52yrs \n" ); document.write( "(5S-4yrs)(S-4yrs)=52yrs \n" ); document.write( "5S^2-24S+16=52 \n" ); document.write( "5S^2-24S-36=0 \n" ); document.write( "(5S+6)(S-6)=0 \n" ); document.write( "5S+6=0 or S-6=0 \n" ); document.write( "5S=-6 or S=6 \n" ); document.write( "S=-5/6 or S=6 \n" ); document.write( "ANSWER 1: Son is 6 years old \n" ); document.write( "M=5(S)=5(6yrs)=30 years old \n" ); document.write( "ANSWER 2: The man is 30 years old. \n" ); document.write( ". \n" ); document.write( "CHECK: \n" ); document.write( "(M-4yrs)(S-4yrs)=52yrs \n" ); document.write( "(30yrs-4yrs)(6yrs-4yrs)=52yrs \n" ); document.write( "(26yrs)(2yrs)=52yrs \n" ); document.write( "52yrs=52yrs \n" ); document.write( " \n" ); document.write( " |