document.write( "Question 982712: Please help me solve this problem: \r
\n" ); document.write( "\n" ); document.write( "Graph the following using intercepts. y= 2 sqrt(x+9)-4
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Algebra.Com's Answer #603539 by josgarithmetic(39620)\"\" \"About 
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Upper branch of a horizontal parabola, concave to the right. Translated from reference position by 9 units to the left and 4 units downward. The reference function equation would be \"y=2%2Asqrt%28x%29\". You will find that instead of this vertex at origin, your given equation has vertex moved to (-9,-4).\r
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\n" ); document.write( "\n" ); document.write( "\"graph%28300%2C300%2C-10%2C2%2C-5%2C7%2C2%2Asqrt%28x%2B9%29-4%29\"\r
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\n" ); document.write( "The question was, or assigned task was to graph USING THE INTERCEPTS.
\n" ); document.write( "Let each variable be 0, one at a time, and solve for the other variable.\r
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\n" ); document.write( "\n" ); document.write( "If y is 0,
\n" ); document.write( "\"2sqrt%28x%2B9%29-4=0\"
\n" ); document.write( "\"2sqrt%28x%2B9%29=4\"
\n" ); document.write( "\"sqrt%28x%2B9%29=2\"
\n" ); document.write( "\"%28sqrt%28x%2B9%29%29%5E2=4\"
\n" ); document.write( "\"x%2B9=4\"
\n" ); document.write( "\"x=4-9\"
\n" ); document.write( "\"x=-5\"
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\n" ); document.write( "Then this is the intercept (-5,0). This is seen on the graph, also can be helpful in making the graph.\r
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\n" ); document.write( "\n" ); document.write( "If x is zero,
\n" ); document.write( "\"y=2sqrt%280%2B9%29-4\"
\n" ); document.write( "\"y=2%2A3-4\"
\n" ); document.write( "\"y=6-4=2\"
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\n" ); document.write( "The y intercept, (0,2).
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