document.write( "Question 982722: I need help with this problem. Use Descartes' rule of signs to determine the possible numbers of:
\n" ); document.write( "a) Positive real roots of $\"x%5E4+%2B+x%5E3+-+3x%5E2+%2B+x+%2B+2+=+0\"$
\n" ); document.write( "b) Negative real roots of $\"x%5E4+%2B+x%5E3+-+3x%5E2+%2B+x+%2B+2+=+0\"$
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Algebra.Com's Answer #603512 by solver91311(24713) $\"\"$ $\"About$

You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "Positive case: Two sign changes, so either two positive real roots or zero positive real roots.\r
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\n" ); document.write( "\n" ); document.write( "Negative case:

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\n" ); document.write( "\n" ); document.write( "which is to say:\r
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\n" ); document.write( "\n" ); document.write( "Again, two sign changes so there are either two negative real roots or zero negative real roots.\r
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\n" ); document.write( "\n" ); document.write( "John
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\n" ); document.write( "My calculator said it, I believe it, that settles it\r
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