document.write( "Question 982695: a father is 28 yrs older than his daughter , in two years time he will be three times as old as his daughter . find their present ages
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Algebra.Com's Answer #603495 by Cromlix(4381)\"\" \"About 
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Hi there,
\n" ); document.write( "a father is 28 yrs older than his daughter
\n" ); document.write( "F = 28 + D....(1)
\n" ); document.write( "in two years time he will be three times
\n" ); document.write( "as old as his daughter
\n" ); document.write( "F + 2 = 3(D + 2)....(2)
\n" ); document.write( "Replace F in Eq(1) with
\n" ); document.write( "(28 + D) from Eq(2)
\n" ); document.write( "F + 2 = 3(D + 2)
\n" ); document.write( "28 + D + 2 = 3(D + 2)
\n" ); document.write( "Collect like terms
\n" ); document.write( "30 + D = 3D + 6
\n" ); document.write( "D - 3D = 6 - 30
\n" ); document.write( "-2D = -24
\n" ); document.write( "Multiply both sides by -1
\n" ); document.write( "2d = 24
\n" ); document.write( "D = 12
\n" ); document.write( "Current ages.
\n" ); document.write( "Daughter = 12 yrs old
\n" ); document.write( "Father = 40 yrs old
\n" ); document.write( "Hope this helps:-)
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