document.write( "Question 982594: jack and jerry can complete a job together in 4 hours. if jack require 6 hours to do the job alone, how many hours will it take jerry to do the job alone.
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document.write( "A.12
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document.write( "B.10
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document.write( "C.8
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document.write( "D.6
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document.write( "E.4 \n" );
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Algebra.Com's Answer #603450 by ptaylor(2198) You can put this solution on YOUR website! Let x=time it takes Jerry to do the job alone \n" ); document.write( "Then Jerry works at the rate of 1/x of the job per hour \n" ); document.write( "And Jack works at the rate of 1/6 of the job per hour \n" ); document.write( "Together they work at the rate of 1/4 of the job per hour \n" ); document.write( "Sooooo \n" ); document.write( "1/x + 1/6= 1/4 multiply each term by 12x to get rid of fractions \n" ); document.write( "12 + 2x=3x subtract 2x from each side \n" ); document.write( "x=12 hrs \n" ); document.write( "ck \n" ); document.write( "1/12 + 1/6 =? 1/4 \n" ); document.write( "1/12 + 2/12= 1/4 \n" ); document.write( "1/4=1/4 \n" ); document.write( "Hope this helps----ptaylor \n" ); document.write( " |