document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=982640>Question 982640</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A speed boat can travel at 16km/h in still water. A 60km course takes 2 hours longer against the current than with it. Find the speed of the current. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #603442 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=603442\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let x be the rate of current\r<BR>\n" );
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document.write( "downstream speed = (16+x)<BR>\n" );
document.write( "upstream speed = (16-x)\r<BR>\n" );
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document.write( "t=d/r\r<BR>\n" );
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document.write( "time upstream - time downstream = 2 hours\r<BR>\n" );
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document.write( "distance = 60\r<BR>\n" );
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document.write( "60/(16-x) -60/(16+x) =2\r<BR>\n" );
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document.write( "60(16+x) - 60(16-x)=2(16+x)(16-x)\r<BR>\n" );
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document.write( "960+60x -960+60x=2(256-x^2)\r<BR>\n" );
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document.write( "120x+2x^2-512=0\r<BR>\n" );
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document.write( "2x^2+120x-512=0\r<BR>\n" );
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document.write( "/2<BR>\n" );
document.write( "x^2+60x-256=0\r<BR>\n" );
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document.write( "x^2+64x-4x-256=0\r<BR>\n" );
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document.write( "x(x+64)-4(x+64)=0\r<BR>\n" );
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document.write( "(x-4)(x+64)=0\r<BR>\n" );
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document.write( "x=4 the positive value </SPAN>\n" );
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