document.write( "Question 982598: On a particular day, the wind added 4 miles per hour to Jaime's rate when she was rowing with the wind and subtracted 4 miles per hour from her rate on her return trip. Jaime found that in the same amount of time she could row 34 miles with the wind, she could go only 18 miles against the wind. What is her normal rowing speed with no wind? Please help! \n" ); document.write( "

Algebra.Com's Answer #603421 by mananth(16946) $\"\"$ $\"About$

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On a particular day, the wind added 4 miles per hour to Jaime's rate when she was rowing with the wind and subtracted 4 miles per hour from her rate on her return trip. Jaime found that in the same amount of time she could row 34 miles with the wind, she could go only 18 miles against the wind. What is her normal rowing speed with no wind? \r
\n" ); document.write( "\n" ); document.write( "let speed of boat in still water be x
\n" ); document.write( "rate of wind =4\r
\n" ); document.write( "\n" ); document.write( "with wind rate = x+4
\n" ); document.write( "distance with wind = 34 miles\r
\n" ); document.write( "\n" ); document.write( "against wind rate = x-4
\n" ); document.write( "distance against wind = 18 miles\r
\n" ); document.write( "\n" ); document.write( "t = d/r\r
\n" ); document.write( "\n" ); document.write( "time against wind = time with wind\r
\n" ); document.write( "\n" ); document.write( "34/(x+4) = 18/(x-4)\r
\n" ); document.write( "\n" ); document.write( "34(x-4)=18(x+4)\r
\n" ); document.write( "\n" ); document.write( "34x-136 =18x+72\r
\n" ); document.write( "\n" ); document.write( "34x-18x=72+136
\n" ); document.write( "16x=208
\n" ); document.write( "x=13 mph\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

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