document.write( "Question 982515: Channing derives an income of P618 from some money invested at 3% and some at 4.5% if the amounts of the respective investmemts were interchanged, he would receive P336. How much did he originally invest at each rate? \n" ); document.write( "
Algebra.Com's Answer #603420 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Channing derives an income of P618 from some money invested at 3% and some at 4.5% if the amounts of the respective investments were interchanged, he would receive P336. \n" ); document.write( " How much did he originally invest at each rate? \n" ); document.write( "; \n" ); document.write( "let x = amt of 1st investment \n" ); document.write( "let y = amt of 2nd investment \n" ); document.write( ": \n" ); document.write( "Write an equation for each scenario \n" ); document.write( ".045x + .03y = 636 \n" ); document.write( ".03x + .045y = 618 \n" ); document.write( ": \n" ); document.write( "Rearrange the 1st equation \n" ); document.write( ".03y = -.045x + 636 \n" ); document.write( "divide both sides by .03 \n" ); document.write( "y = \n" ); document.write( "y = -1.5x + 21200 \n" ); document.write( ": \n" ); document.write( "Replace y with (-1.5x+21200) in the 2nd equation \n" ); document.write( ".03x + .045(-1.5x+21200) = 618 \n" ); document.write( ".03x - .0675x + 954 = 618 \n" ); document.write( ".03x - .0675x = 618 - 954 \n" ); document.write( "-.0375x = -336 \n" ); document.write( "x = \n" ); document.write( "x = $8960 amt in the 1st investment \n" ); document.write( "then \n" ); document.write( "y = -1.5(8960) + 21200 \n" ); document.write( "y = -13440 + 21200 \n" ); document.write( "y = $7760 amt in the 2nd investment \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "You can check this for yourself: \n" ); document.write( " .03(8960) + .045(7760) = \n" ); document.write( "and \n" ); document.write( " .045(8960) + .03(7760) = \n" ); document.write( " \n" ); document.write( " |