document.write( "Question 982597: Please help me answer these questions:
\n" ); document.write( "Rewrite the following square roots when x<-3:
\n" ); document.write( "1) \"sqrt%28%28x-2%29%5E2%29\"
\n" ); document.write( "The answer I got for this was -(x-2), when x>2 and x-2 when x< or equal to-2 but i'm not sure if this is right. \r
\n" ); document.write( "\n" ); document.write( "2) \"sqrt%28%28x%2B2%29%5E2%29\"
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Algebra.Com's Answer #603414 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
\"sqrt%28%28%28xLessThanNegThree%29-2%29%5E2%29\", the binomial will be a negative number but then still inside the square root function, the binomial is being squared and becomes positive.\r
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\n" ); document.write( "\n" ); document.write( "Also, understand that \"abs%28x-2%29=sqrt%28%28x-2%29%5E2%29\", and the critical x value is 2. Negative 3 clearly makes \"x-2%3C0\".\r
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\n" ); document.write( "\n" ); document.write( "\"abs%28x-2%29\" when \"x-2\" is negative becomes \"abs%28x-2%29=-%28x-2%29=highlight%28-x%2B2%29\".\r
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\n" ); document.write( "\n" ); document.write( "The second equation to analyze will work similarly. x+2 will be negative for \"x%3C-3\".
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