document.write( "Question 982595: The supplement of an angle measures 11 times its complement. Then the measure of the angle is...
\n" ); document.write( "A. 9 degrees
\n" ); document.write( "B. 81 degrees
\n" ); document.write( "C. 90 degrees
\n" ); document.write( "D. 99 degrees
\n" ); document.write( "E. 100 degrees
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Algebra.Com's Answer #603412 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "Two Angles are Supplementary when they add up to \"180\" degrees.\r
\n" ); document.write( "\n" ); document.write( "Complementary Angles add up to \"90\"°.\r
\n" ); document.write( "\n" ); document.write( "if one angle is \"alpha\", its supplement is \"180-alpha\" and its complement is \"90-alpha\"\r
\n" ); document.write( "\n" ); document.write( "if the supplement of an angle measures \"11\" times its complement, then we have \r
\n" ); document.write( "\n" ); document.write( "\"180-alpha=11%2890-alpha%29\" \r
\n" ); document.write( "\n" ); document.write( "\"180-alpha=990-11alpha\" \r
\n" ); document.write( "\n" ); document.write( "\"11alpha-alpha=990-180\" \r
\n" ); document.write( "\n" ); document.write( "\"10alpha=810\" \r
\n" ); document.write( "\n" ); document.write( "\"alpha=810%2F10\" \r
\n" ); document.write( "\n" ); document.write( "\"highlight%28alpha=81%29\"° \r
\n" ); document.write( "\n" ); document.write( "so, \"alpha=81\"° , its supplement is \"180-alpha=180-81=99\" and its complement is \"90-alpha=90-81=9\"\r
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\n" ); document.write( "\n" ); document.write( "your answer is: B. \"81\" degrees\r
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