document.write( "Question 982494: Hi, here's my question:\r
\n" ); document.write( "\n" ); document.write( "Charlie rows at a constant speed downstream in the river from Amaroo to Bradden in 3 hours and back upstream in 4 hours. Assume the river flows at a constant rate. Let the river's flowing rate be xkm/hr and Charlie's rowing speed (km/hr) be y km/hr, express y in terms of x.\r
\n" ); document.write( "\n" ); document.write( "Please include an understandable explanation and thank you so so much! :) \n" ); document.write( "
Algebra.Com's Answer #603409 by macston(5194)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "Distance between two places stays the same:
\n" ); document.write( "D=distance
\n" ); document.write( "Rate downstream is rowing+current=y+x
\n" ); document.write( "Rate upstream is rowing-current=y-x
\n" ); document.write( "Distance=rate x time
\n" ); document.write( ".
\n" ); document.write( "Upstream:
\n" ); document.write( "D=(y-x)(4hrs)
\n" ); document.write( "Downstream:
\n" ); document.write( "D=(y+x)(3hrs)
\n" ); document.write( ".
\n" ); document.write( "Since D=D:
\n" ); document.write( "(y-x)(4hrs)=(y+x)(3hrs)
\n" ); document.write( "(4y)hrs-(4x)hrs=(3y)hrs+(3x)hrs
\n" ); document.write( "(y)hrs=(7x)hrs Divide each side by 1 hour.
\n" ); document.write( "y=7x
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