document.write( "Question 982554: Suppose a car and a truck both leave from Johannesburg. The car leaves at 09:00, and the truck leaves 45 minutes earlier. The car travels at 120 km/h and the truck travels at 90 km/h. How far away from Johannesburg will they meet? \n" ); document.write( "
Algebra.Com's Answer #603370 by josmiceli(19441)\"\" \"About 
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What distance is the truck's head start?
\n" ); document.write( "( 45 min is 3/4 of an hour )
\n" ); document.write( "\"+d%5B1%5D+=+90%2A%283%2F4%29+\"
\n" ); document.write( "\"+d%5B1%5D+=+67.5+\" km
\n" ); document.write( "----------------------
\n" ); document.write( "Start a stopwatch when the car leaves at 9:00
\n" ); document.write( "Let \"+t+\" = time in hours on stopwatch when
\n" ); document.write( "car catches up with the truck
\n" ); document.write( "Let \"+d+\" distance the car travels until it
\n" ); document.write( "catches up with the truck
\n" ); document.write( "-----------------------
\n" ); document.write( "Equation for the car:
\n" ); document.write( "(1) \"+d+=+120t+\"
\n" ); document.write( "Equation for the truck:
\n" ); document.write( "(2) \"+d+-+67.5+=+90t+\"
\n" ); document.write( "----------------------
\n" ); document.write( "(1) \"+t+=+d%2F120+\"
\n" ); document.write( "(2) \"+d+-+67.5+=+%28+90%2F120+%29%2Ad+\"
\n" ); document.write( "(2) \"+d+-+67.5+=+.75d+\"
\n" ); document.write( "(2) \"+.25d+=+67.5+\"
\n" ); document.write( "(2) \"+d+=+270+\"
\n" ); document.write( "-----------------
\n" ); document.write( "They meet 270 km from Johannesburg
\n" ); document.write( "check:
\n" ); document.write( "(1) \"+d+=+120t+\"
\n" ); document.write( "(1) \"+270+=+120t+\"
\n" ); document.write( "(1) \"+t+=+2.25+\"
\n" ); document.write( "and
\n" ); document.write( "(2) \"+d+-+67.5+=+90t+\"
\n" ); document.write( "(2) \"+270+-+67.5+=+90t+\"
\n" ); document.write( "(2) \"+202.5+=+90t+\"
\n" ); document.write( "(2) \"+t+=+2.25+\"
\n" ); document.write( "OK
\n" ); document.write( "( note that they meet at 11:15 )\r
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