document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=982479>Question 982479</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can someone please help me with my homework? Thanks :D<BR>\n" );
document.write( "1.What if I have +&#8730;3 and -&#8730;3 as the roots. What is the equation?<BR>\n" );
document.write( "2. Graph the equation in a sign graph: x^2+8x-7=0<BR>\n" );
document.write( "In question no. 2, I find the roots of it first. Since it's not a perfect square trinomial, and 8 is an even number, I used completing the square.<BR>\n" );
document.write( "x^2+8x=7<BR>\n" );
document.write( "x^2+8x+(8/2)^2=7+(8/2)^2<BR>\n" );
document.write( "x^2+8x+16=23<BR>\n" );
document.write( "x^2+8x+16-23=0<BR>\n" );
document.write( "x^2+8x-7=0<BR>\n" );
document.write( "But i ended up returning to the original equation :/<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #603303 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=603303\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x^2+8x=7<BR>\n" );
document.write( "x^2+8x+(8/2)^2=7+(8/2)^2<BR>\n" );
document.write( "x^2+8x+16=23<BR>\n" );
document.write( "x^2+8x+16=23\r<BR>\n" );
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document.write( "(x+4)^2 = 23\r<BR>\n" );
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document.write( "(x+4) = +/-sqrt(23)\r<BR>\n" );
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document.write( "x= -4 +/- sqrt(23)\r<BR>\n" );
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document.write( "sum of roots = 0<BR>\n" );
document.write( "product of roots = -3\r<BR>\n" );
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document.write( "x^2-(sum of roots)x+(product of roots =0\r<BR>\n" );
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document.write( "x^2-3=0 is the equation </SPAN>\n" );
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