document.write( "Question 982451: find the zeros of a function \r
\n" ); document.write( "\n" ); document.write( "y= (x^2+2x-7)(x^3+4x^2-21x)\r
\n" ); document.write( "\n" ); document.write( " I forgot how to do these, can someone please help?
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Algebra.Com's Answer #603297 by ikleyn(52803)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "To find zeroes of a polynomial \r
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\n" ); document.write( "\n" ); document.write( "\"y\" = \"%28x%5E2%2B2x-7%29\".\"%28x%5E3%2B4x%5E2-21x%29\"\r
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\n" ); document.write( "\n" ); document.write( "you need to find zeroes of the first factor  \"%28x%5E2%2B2x-7%29\"  and the the zeroes of the second factor  \"%28x%5E3%2B4x%5E2-21x%29\". \r
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\n" ); document.write( "\n" ); document.write( "The first factor  \"%28x%5E2%2B2x-7%29\"  has the zeroes  \"x%5B1%5D\" = \"-1+%2B+2sqrt%282%29\"  and  \"x%5B2%5D\" = \"-1+-+2sqrt%282%29\"  (use the quadratic formula). \r
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\n" ); document.write( "\n" ); document.write( "The second factor is  \"%28x%5E3%2B4x%5E2-21x%29\" = \"x\".\"%28x%5E2%2B4x-21%29\". \r
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\n" ); document.write( "\n" ); document.write( "It has the zeroes  \"x%5B3%5D\" = \"0\",  \"x%5B4%5D\" = \"4\",  and  \"x%5B5%5D\" = \"-7\". \r
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\n" ); document.write( "\n" ); document.write( "The first of these three zeroes is obvious  (\"x%5B3%5D\" = \"0\").\r
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\n" ); document.write( "\n" ); document.write( "The two others of these three zeroes you can obtain using the quadratic formula or the Viete's theorem \r
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\n" ); document.write( "\n" ); document.write( "Answer.  The zeroes are  \"-1+%2B+2sqrt%282%29\",  \"-1+-+2sqrt%282%29\",  \"0\",  \"4\"  and  \"-7\". \r
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