document.write( "Question 982437: Use the Factor Theorem to determine whether the first polynomial is a factor of the second.\r
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document.write( "x-2; 4x³-3x²-8x+4 \n" );
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Algebra.Com's Answer #603269 by Edwin McCravy(20060)![]() ![]() You can put this solution on YOUR website! \r\n" ); document.write( "x-2; 4x³-3x²-8x+4\r\n" ); document.write( "\r\n" ); document.write( "Change the sign of the number -2 in x-2, to +2.\r\n" ); document.write( "\r\n" ); document.write( "Put it on the left of the synthetic division:\r\n" ); document.write( "\r\n" ); document.write( "2 | 4 -3 -8 4\r\n" ); document.write( " | 8 10 4\r\n" ); document.write( " 4 5 2 8\r\n" ); document.write( "\r\n" ); document.write( "The last number on the bottom row, which is the remainder, \r\n" ); document.write( "is not 0, it's 8. Therefore x-2 is not a factor of \r\n" ); document.write( "4x³-3x²-8x+4. \r\n" ); document.write( "\r\n" ); document.write( "---------------------\r\n" ); document.write( "\r\n" ); document.write( "Note:\r\n" ); document.write( "If the polynomial had been 4x³-3x²-8x-4 (where the last term \r\n" ); document.write( "were -4 instead of +4, then the synthetic division would have \r\n" ); document.write( "been:\r\n" ); document.write( "\r\n" ); document.write( "2 | 4 -3 -8 -4\r\n" ); document.write( " | 8 10 4\r\n" ); document.write( " 4 5 2 0\r\n" ); document.write( "\r\n" ); document.write( "Then x-2 would have been a factor of 4x³-3x²-8x-4, because\r\n" ); document.write( "the last term, which is the remainder, would have been 0 \r\n" ); document.write( "and the factorization would have been\r\n" ); document.write( "\r\n" ); document.write( "(x-2)(4x²+5x+2) using the numbers on the bottom row as \r\n" ); document.write( "coefficient of a polynomial of one less degree.\r\n" ); document.write( "\r\n" ); document.write( "However with the +4 on the end x-2 is not a factor.\r\n" ); document.write( "\r\n" ); document.write( "Edwin\n" ); document.write( " |