document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=982439>Question 982439</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Use the Factor Theorem to determine whether the first polynomial is a factor of the second.\r<BR>\n" );
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document.write( "x + 3; 2x^3 + x^2 - 13x +6 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #603266 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=603266\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  Use the Factor Theorem to determine whether the first polynomial is a factor of the second. <BR>\n" );
document.write( "x + 3; 2x^3 + x^2 - 13x +6<BR>\n" );
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document.write( "If x+3 is a factor, f(-3) = 0<BR>\n" );
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document.write( "Using synthetic division you get:<BR>\n" );
document.write( "-3)....2....1....-13....6<BR>\n" );
document.write( ".......2....-5....2...|..0\r<BR>\n" );
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document.write( "Since the remainder is zero, f(-3)=0, and x+3 is a factor.\r<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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