document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=982439>Question 982439</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Use the Factor Theorem to determine whether the first polynomial is a factor of the second.\r<BR>\n" );
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document.write( "x + 3; 2x^3 + x^2 - 13x +6 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #603265 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39617)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=603265\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Same as synthetic division to check the roots  -3  for the polynomial function 2x^3+x^2-13x+6.\r<BR>\n" );
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document.write( "If remainder is 0, then -3 is a root and x+3 is a factor.  That's what the Factor Theorem means.\r<BR>\n" );
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document.write( "-3________|______2______1_______-13_______6<BR>\n" );
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document.write( "__________|____________-6_______15________-6<BR>\n" );
document.write( "__________|_____________________________________<BR>\n" );
document.write( "________________2_____-5________2________0\r<BR>\n" );
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document.write( "Remainder IS zero, so x+3 is a factor of the given polynomial function. </SPAN>\n" );
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