document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=982448>Question 982448</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how much water is to be evaporated from 20 liters of 20 percent sugar solution to get 30 percent sugar solution. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #603253 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=603253\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> how much water is to be evaporated from 20 liters of 20 percent sugar solution to get 30 percent sugar solution.<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "water - water = water<BR>\n" );
document.write( "0.80*20 - 1*x = 0.70(20-x)<BR>\n" );
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document.write( "Multiply thru by 100 to get:<BR>\n" );
document.write( "80*20 - 100x = 70*20 - 70x<BR>\n" );
document.write( "30x = 10*20<BR>\n" );
document.write( "x = (1/3)20 = 6 2/3 Liters (amt. of water to evaporate)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "------------ </SPAN>\n" );
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