document.write( "Question 982373: when the tens digit of three digit number abc deleted a two digit number ac is formed. How many numbers abc are thee such that abc = 9ac+4c? \n" ); document.write( "
Algebra.Com's Answer #603251 by ankor@dixie-net.com(22740)\"\" \"About 
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when the tens digit of three digit number abc deleted a two digit number ac is formed.
\n" ); document.write( " How many numbers abc are there such that abc = 9ac+4c?
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\n" ); document.write( "the equation representing the 3 digit and 2 digit number
\n" ); document.write( "100a + 10b + c = 9(10a+c) + 4c
\n" ); document.write( "There are 3 unknowns here, let's assume that c=5, then we can simplify.
\n" ); document.write( "100a + 10b + 5 = 9(10a+5) + 4(5)
\n" ); document.write( "100a + 10b + 5 = 90a + 45 + 20
\n" ); document.write( "100a - 90a + 10b = 65 - 5
\n" ); document.write( "10a + 10b = 60
\n" ); document.write( "simplify, divide by 10
\n" ); document.write( "a + b = 6
\n" ); document.write( "How many 3 digit numbers can we have from this, assuming c = 5?
\n" ); document.write( "ABC
\n" ); document.write( "155
\n" ); document.write( "245
\n" ); document.write( "335
\n" ); document.write( "425
\n" ); document.write( "515
\n" ); document.write( "605
\n" ); document.write( "At least 6 numbers will satisfy our initial requirement
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\n" ); document.write( "I confirmed this with a little basic program I wrote, these are the only numbers that will work\r
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