document.write( "Question 83867: What is the vertex and axis of symmetry of the equation y=-2x^2+x+1?
\n" ); document.write( "So far I have x=-1+or-sqrt1^2+4(-2)*1/2(-2) and have found the x intercepts to be (-1/2,1).
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Algebra.Com's Answer #60325 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
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Solved by pluggable solver: Completing the Square to Get a Quadratic into Vertex Form

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\n" ); document.write( " \"y=-2+x%5E2%2B1+x%2B1\" Start with the given equation
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\n" ); document.write( " \"y-1=-2+x%5E2%2B1+x\" Subtract \"1\" from both sides
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\n" ); document.write( " \"y-1=-2%28x%5E2%2B%28-1%2F2%29x%29\" Factor out the leading coefficient \"-2\"
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\n" ); document.write( " Take half of the x coefficient \"-1%2F2\" to get \"-1%2F4\" (ie \"%281%2F2%29%28-1%2F2%29=-1%2F4\").
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\n" ); document.write( " Now square \"-1%2F4\" to get \"1%2F16\" (ie \"%28-1%2F4%29%5E2=%28-1%2F4%29%28-1%2F4%29=1%2F16\")
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\n" ); document.write( " \"y-1=-2%28x%5E2%2B%28-1%2F2%29x%2B1%2F16-1%2F16%29\" Now add and subtract this value inside the parenthesis. Doing both the addition and subtraction of \"1%2F16\" does not change the equation
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\n" ); document.write( " \"y-1=-2%28%28x-1%2F4%29%5E2-1%2F16%29\" Now factor \"x%5E2%2B%28-1%2F2%29x%2B1%2F16\" to get \"%28x-1%2F4%29%5E2\"
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\n" ); document.write( " \"y-1=-2%28x-1%2F4%29%5E2%2B2%281%2F16%29\" Distribute
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\n" ); document.write( " \"y-1=-2%28x-1%2F4%29%5E2%2B1%2F8\" Multiply
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\n" ); document.write( " \"y=-2%28x-1%2F4%29%5E2%2B1%2F8%2B1\" Now add \"1\" to both sides to isolate y
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\n" ); document.write( " \"y=-2%28x-1%2F4%29%5E2%2B9%2F8\" Combine like terms
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\n" ); document.write( " Now the quadratic is in vertex form \"y=a%28x-h%29%5E2%2Bk\" where \"a=-2\", \"h=1%2F4\", and \"k=9%2F8\". Remember (h,k) is the vertex and \"a\" is the stretch/compression factor.
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\n" ); document.write( " Check:
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\n" ); document.write( " Notice if we graph the original equation \"y=-2x%5E2%2B1x%2B1\" we get:
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\n" ); document.write( " \"graph%28500%2C500%2C-10%2C10%2C-10%2C10%2C-2x%5E2%2B1x%2B1%29\" Graph of \"y=-2x%5E2%2B1x%2B1\". Notice how the vertex is (\"1%2F4\",\"9%2F8\").
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\n" ); document.write( " Notice if we graph the final equation \"y=-2%28x-1%2F4%29%5E2%2B9%2F8\" we get:
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\n" ); document.write( " \"graph%28500%2C500%2C-10%2C10%2C-10%2C10%2C-2%28x-1%2F4%29%5E2%2B9%2F8%29\" Graph of \"y=-2%28x-1%2F4%29%5E2%2B9%2F8\". Notice how the vertex is also (\"1%2F4\",\"9%2F8\").
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\n" ); document.write( " So if these two equations were graphed on the same coordinate plane, one would overlap another perfectly. So this visually verifies our answer.
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