document.write( "Question 83865: Hi can u please help me with this thanks!
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document.write( "- Match the real-life object with its measurement.
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document.write( "A/2.95 dm B/122m C/1mm D/66cm\r
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document.write( "1. Diameter of a bicycle wheel
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document.write( "2. Distance from home plate to center field in a professional baseball park
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document.write( "3. Thickness of a CD
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document.write( "4. Length of a man's size 9 sneaker\r
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document.write( "Can you match those up please thank you so much! \n" );
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Algebra.Com's Answer #60322 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! - Match the real-life object with its measurement. \n" ); document.write( "A/2.95 dm B/122m C/1mm D/66cm\r \n" ); document.write( "\n" ); document.write( "1. Diameter of a bicycle wheel \n" ); document.write( "2. Distance from home plate to center field in a professional baseball park \n" ); document.write( "3. Thickness of a CD \n" ); document.write( "4. Length of a man's size 9 sneaker\r \n" ); document.write( "\n" ); document.write( "--------------------- \n" ); document.write( "mm is 1/1000 th of a meter \n" ); document.write( "cm is 1/100 th of a meter \n" ); document.write( "dm is 1/10 th of a meter \n" ); document.write( "m is 1 meter\r \n" ); document.write( "\n" ); document.write( "------------- \n" ); document.write( "B is 122 meters so must be distance from home plate to center field \n" ); document.write( "C is 1/1000 of a meter so must be the thickness of a CD \n" ); document.write( "A is 2.95 dm which is 29.5 cm which is about 8 inches so must be lenght \n" ); document.write( "of a man's size 9 sneaker \n" ); document.write( "D is 66 cm which is about 25 inches which must be the diameter of a bicycle \n" ); document.write( "wheel \n" ); document.write( "=============== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |