document.write( "Question 982401: The length of a rectangle is six more than twice the width. If the area is 20 square inches, find the dimensions of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #603218 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! The length of a rectangle is six more than twice the width. If the area is 20 square inches, find the dimensions of the rectangle. \n" ); document.write( "--------------- \n" ); document.write( "width = w \n" ); document.write( "length = 2w+6 \n" ); document.write( "-------- \n" ); document.write( "Equation: \n" ); document.write( "w(2w+6) = 20 \n" ); document.write( "2w^2+6w-20 = 0 \n" ); document.write( "------ \n" ); document.write( "w^2 + 3w - 10 = 0 \n" ); document.write( "(w+5)(w-2) = 0 \n" ); document.write( "---- \n" ); document.write( "Positive solution:: \n" ); document.write( "width = 2 inches; then length = 2*2+6 = 10 inches \n" ); document.write( "---------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "--------------- \n" ); document.write( " |