document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=982405>Question 982405</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A freight train takes 18 hours to travel the same distance that an express t rain travels in 15 hours. The rate of the express train is 15 miles per hour faster than the freight train. Find the rate at which each train travels. </SPAN>\n" );
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document.write( "distance=rate x time<BR>\n" );
document.write( "Since distance is the same:<BR>\n" );
document.write( "rate of express x 15 hours=rate of freight x 18 hours<BR>\n" );
document.write( "rate of express=rate of freight + 15mph<BR>\n" );
document.write( "Let F=rate of freight train:<BR>\n" );
document.write( ".<BR>\n" );
document.write( "(F+15mph)(15hrs)=F(18hrs)<BR>\n" );
document.write( "15F+225=18F<BR>\n" );
document.write( "225=3F<BR>\n" );
document.write( "75mph=F ANSWER 1: The freight train travels at 75 mph.<BR>\n" );
document.write( "Express=Freight + 15 mph=75mph+15mph=90mph<BR>\n" );
document.write( "ANSWER 2: The express train travels at 90 mph.<BR>\n" );
document.write( ".<BR>\n" );
document.write( "CHECK:<BR>\n" );
document.write( "(90mph)(15hrs)=(75mph)(18hrs)<BR>\n" );
document.write( "1350 miles=1350 miles </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );