document.write( "Question 982391: -1 + 2ln(x-2) = ln(x) \n" ); document.write( "
Algebra.Com's Answer #603209 by Edwin McCravy(20060)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "Notice that I've changed the numbers, so you'll have to go\r\n" );
document.write( "through it, using this as a model.  Yours is done EXACTLY \r\n" );
document.write( "the same way:\r\n" );
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document.write( "\"-3+%2B+2%2Aln%28x-3%29+=+ln%28x%29\"\r\n" );
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document.write( "\"-3+%2B+2%2Aln%28x-3%29+=+ln%28x%29\"\r\n" );
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document.write( "\"2%2Aln%28x-3%29-ln%28x%29+=+3\"\r\n" );
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document.write( "\"ln%28x-3%29%5E2-ln%28x%29+=+3\"\r\n" );
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document.write( "\"ln%28%28x-3%29%5E2%2Fx%29=e\"\r\n" );
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document.write( "\"%28x-3%29%5E2%2Fx=e%5E3\"\r\n" );
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document.write( "\"%28x-3%29%5E2=e%5E3%2Ax\"\r\n" );
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document.write( "\"x%5E2-6x%2B9=e%5E3%2Ax\"\r\n" );
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document.write( "\"x%5E2-6x%2B9-e%5E3%2Ax=0\"\r\n" );
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document.write( "\"x%5E2-6x-e%5E3%2Ax%2B9=0\"\r\n" );
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document.write( "\"x%5E2-x%286%2Be%5E3%29%2B9=0\"\r\n" );
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document.write( "\"x%5E2-%286%2Be%5E3%29x%2B9=0\"\r\n" );
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document.write( "\"a=1\", \"b=-%286%2Be%5E3%29\", \"c=9%29\"\r\n" );
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document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4ac+%29%29%2F%282a%29+\"\r\n" );
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document.write( "\"x+=+%28%286%2Be%5E3%29+%2B-+sqrt%28%286%2Be%5E3%29%5E2-36+%29%29%2F2+\"\r\n" );
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document.write( "\"x+=+%286%2Be%5E3+%2B-+sqrt%28%2836%2B12e%5E3%2Be%5E6%29-36+%29%29%2F2+\"\r\n" );
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document.write( "\"x+=+%286%2Be%5E3+%2B-+sqrt%2836%2B12e%5E3%2Be%5E6-36+%29%29%2F2+\"\r\n" );
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document.write( "\"x+=+%286%2Be%5E3+%2B-+sqrt%2812e%5E3%2Be%5E6+%29%29%2F2+\"\r\n" );
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document.write( "\"x+=+%286%2Be%5E3+%2B-+sqrt%28e%5E3%2812%2Be%5E3%29%29%29%2F2\"\r\n" );
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document.write( "Using the +, that's approximately 25.7358\r\n" );
document.write( "Using the -, that's approximately 0.3497\r\n" );
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document.write( "However since there is ln(x-2) in the original equation, the\r\n" );
document.write( "value of x-2 must be positive, or x > 2, so we may not use \r\n" );
document.write( "the minus sign.\r\n" );
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document.write( "Solution:\r\n" );
document.write( "x = (6+e^3+sqrt(e^3(12+e^3)))}}}\r\n" );
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document.write( "Now use the above as a model and do your problem.\r\n" );
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document.write( "Edwin
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