document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=982374>Question 982374</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find p so that the numbers 7p + 2, 5p +12, 2p -1,... form an arithmetic<BR>\n" );
document.write( "sequence.<BR>\n" );
document.write( "A. -8 B.-5 C. -13 D. -23 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #603194 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=603194\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> i believe your solution will be p = -23<BR>\n" );
document.write( "when p = -23:<BR>\n" );
document.write( "A1 = 7*-23+2 = -159<BR>\n" );
document.write( "A2 = 5*-23+12 = -103<BR>\n" );
document.write( "A3 = 2*-23-1 = -47<BR>\n" );
document.write( "the difference between A2 and A1 is (-103) - (-149) = 56<BR>\n" );
document.write( "the difference between A2 and A3 is (-47) - (-103) = 56<BR>\n" );
document.write( "in this arithmetic series, the common diffence is 56.<BR>\n" );
document.write( "how was this derived?<BR>\n" );
document.write( "take A2 - A1 and you get the difference between them.<BR>\n" );
document.write( "(5p + 12) - (7p + 2) = (-2p + 10)<BR>\n" );
document.write( "take A3 - A2 and you get the difference between them.<BR>\n" );
document.write( "(2p-1) - (5p + 12) = (-3p - 13)<BR>\n" );
document.write( "since the difference between each element in an arithmetic series must be the same, then set (-2p + 10) equal to (-3p - 13) and solve for p.<BR>\n" );
document.write( "when you do that, you will get p = -23.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );