document.write( "Question 982352: Bert is twice as Chang.five yrs ago the sum of their ages was 23.how old is bert \n" ); document.write( "
Algebra.Com's Answer #603183 by Cromlix(4381)![]() ![]() You can put this solution on YOUR website! Hi there, \n" ); document.write( "Bert is twice as Chang \n" ); document.write( "B = 2C \n" ); document.write( "five yrs ago the sum of their ages was 23 \n" ); document.write( "B - 5 + C - 5 = 23 \n" ); document.write( "Replace B with 2C from first equation. \n" ); document.write( "2C - 5 + C - 5 = 23 \n" ); document.write( "Collect like terms \n" ); document.write( "3C - 10 = 23 \n" ); document.write( "3C = 23 + 10 \n" ); document.write( "3C = 33 \n" ); document.write( "C = 11 \n" ); document.write( "Bert = 22 yrs old \n" ); document.write( "Chang = 11 yrs old \n" ); document.write( "Hope this helps:-) \n" ); document.write( " |