document.write( "Question 982300: An anthropologist finds bone that her instruments measure it as 0.146% of the amount of Carbon-14 the bones would have contained when the person was alive. How long ago did the person die?
\n" ); document.write( "The half life of carbon 14 is 5,730 years. Round your answer to the nearest thousand. \n" ); document.write( "
Algebra.Com's Answer #603158 by ankor@dixie-net.com(22740)\"\" \"About 
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An anthropologist finds bone that her instruments measure it as 0.146% of the amount of Carbon-14 the bones would have contained when the person was alive.
\n" ); document.write( " How long ago did the person die?
\n" ); document.write( "The half life of carbon 14 is 5,730 years.
\n" ); document.write( " Round your answer to the nearest thousand.
\n" ); document.write( ":
\n" ); document.write( "Using the formula: A = Ao*2^(-t/h); where:
\n" ); document.write( "A = amt remaining after t time
\n" ); document.write( "Ao = initial amt
\n" ); document.write( "t = time of decay
\n" ); document.write( "h = half-life of substance (5730 yrs for carbon 14)
\n" ); document.write( ":
\n" ); document.write( "A = .00146
\n" ); document.write( "Ao = 12^(-t/5730) = .00146
\n" ); document.write( "t = time of decay
\n" ); document.write( "h = 5730
\n" ); document.write( ":
\n" ); document.write( "1*2^(-t/5730) = .00146
\n" ); document.write( "using nat logs
\n" ); document.write( "ln(2^(-t/5730)) = ln(.00146)
\n" ); document.write( "exponent equiv
\n" ); document.write( "\"-t%2F5730\"ln(2) = ln(.00146)
\n" ); document.write( "\"-t%2F5730\" = \"ln%28.00146%29%2Fln%282%29\"
\n" ); document.write( "use your calc
\n" ); document.write( "\"-t%2F5730\" = -9.4198
\n" ); document.write( "t = -5730 * -9.4198
\n" ); document.write( "t = 53,975 yrs \n" ); document.write( "
\n" );