document.write( "Question 982288: Find an equation in standard form for the hyperbola with vertices at (0, ±10) and asymptotes at
\n" ); document.write( "y = ± 5/4 x\r
\n" ); document.write( "\n" ); document.write( "Here is my work, I would just like to double check my work:
\n" ); document.write( "y= +/- (b/a)x\r
\n" ); document.write( "\n" ); document.write( "x^2/a^2- y^2/b^2 = 1\r
\n" ); document.write( "\n" ); document.write( "x^2/16 - y^2/25 =1 \r
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\n" ); document.write( "\n" ); document.write( "Thank you in advance!
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Algebra.Com's Answer #603134 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "Close, but no cigar. For a hyperbola centered at the origin, the vertices are at (0,-a) and (0,a). You were correct to say that a and b are in the ratio 5/4 because of the slopes of the asymptote equations, but you left off the step where you should have calculated the correct value of b based on the fact that a = 10 because of the specification of the vertices.\r
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\n" ); document.write( "\n" ); document.write( "Solve for b and give your equation another try.\r
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\n" ); document.write( "\n" ); document.write( "John
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\n" ); document.write( "My calculator said it, I believe it, that settles it\r
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