document.write( "Question 83818: A ball is thrown upward from the roof of a building 100 m tall with an initial velocity of 20 m/s. When will the ball reach a height of 80 m? \n" ); document.write( "
Algebra.Com's Answer #60313 by ankor@dixie-net.com(22740)\"\" \"About 
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A ball is thrown upward from the roof of a building 100 m tall with an initial velocity of 20 m/s. When will the ball reach a height of 80 m?
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\n" ); document.write( "The equation for this: h(x) height and x = time in seconds
\n" ); document.write( "h(x) = -4.9x^2 + 20x + 100
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\n" ); document.write( "To find time when ball is 80 m above the ground:
\n" ); document.write( "-4.9x^2 + 20x + 100 = 80
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\n" ); document.write( "-4.9x^2 + 20x + 100 - 80 = 0
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\n" ); document.write( "-4.9x^2 + 20x + 20 = 0
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\n" ); document.write( "Solve for x to find the time (in seconds) it will be 80 ft above the ground
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\n" ); document.write( "Use the quadratic formula; a=-4.9, b=20, c=20
\n" ); document.write( "\"x+=+%28-20+%2B-+sqrt%28+20%5E2+-+4+%2A+-4.9+%2A+20+%29%29%2F%282%2A-4.9%29+\"
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\n" ); document.write( "\"x+=+%28-20+%2B-+sqrt%28+400+-+%28-392%29%29%29%2F%28-9.8%29+\"; minus a minus = +
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\n" ); document.write( "\"x+=+%28-20+-+sqrt%28+792%29%29%2F%28-9.8%29+\"
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\n" ); document.write( "Do the math here you should get a positive solution of;
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\n" ); document.write( "x = 4.9 seconds for it to be at 80 m
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\n" ); document.write( "A graphical presentation of this event:
\n" ); document.write( "\"+graph%28+300%2C+200%2C+-2%2C+8%2C+-10%2C+125%2C+-4.9x%5E2+%2B+20x+%2B+100%29+\"
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\n" ); document.write( "Notice that when x = 5 sec, it will be at about 80 meters (y)
\n" ); document.write( "Also notice that it will be 20 meters below the height of the building (x=0)
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\n" ); document.write( "Did this make sense to you?
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