document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=982289>Question 982289</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a student who was given a pentagon with four angle measures was asked to find the fifth angle the student said he would use [(n-2)times 180]/n. will his method work?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #603128 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39633)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=603128\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> That method might or might not work, depending on the pentagon.  If not a regular pentagon,  it can still be split into separate triangles.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Pick one vertex.  Connect this with  segments to the two non-adascent vertices.  This will form THREE triangles.<BR>\n" );
document.write( "180 degrees per triangle<BR>\n" );
document.write( "3 triangles<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3%2Atriangles%2A%28180%2F1%29%28degrees%2Ftriangle%29=3%2A180=540%2Adegrees ALIGN=MIDDLE  ALT=\"3%2Atriangles%2A%28180%2F1%29%28degrees%2Ftriangle%29=3%2A180=540%2Adegrees\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "The division by n WILL NOT WORK as a way to find the degrees per angle UNLESS this is a regular polygon.  The above calculation is for 540 TOTAL degrees for the interior angles of the pentagon. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );