document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=982265>Question 982265</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One number is 17 more than twice a second number. If three times the second number is subtracted from five time the first, the result is 9. Find the two numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #603101 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=603101\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .<BR>\n" );
document.write( "F=first number; S=second number<BR>\n" );
document.write( ".<BR>\n" );
document.write( "F=2S+17<BR>\n" );
document.write( "5F-3S=9 Substitute for F<BR>\n" );
document.write( "5(2S+17)-3S=9<BR>\n" );
document.write( "10S+85-3S=0<BR>\n" );
document.write( "7S=-76<BR>\n" );
document.write( "S=-(76/7)<BR>\n" );
document.write( ".<BR>\n" );
document.write( "F=2S+17<BR>\n" );
document.write( "F=2(-76/7)+17<BR>\n" );
document.write( "F=-152/7+119/7=-33/7<BR>\n" );
document.write( ".<BR>\n" );
document.write( "CHECK:<BR>\n" );
document.write( "5F-3S=9<BR>\n" );
document.write( "5(-33/7)-3(-76/7)=9<BR>\n" );
document.write( "-165/7-(-228/7)=9<BR>\n" );
document.write( "63/7=9<BR>\n" );
document.write( "9=9 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );