document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=982181>Question 982181</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A sum of money amounting to $5.20 consists of quarters and dimes. If there are 31 coins in all, how many of each kind are there?\r<BR>\n" );
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document.write( "A man has $10.40 in change consisting of 3 times as many quarters and nickels. How many quarters and nickels does he have? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #603042 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=603042\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let quarters be x<BR>\n" );
document.write( "and dimes be y\r<BR>\n" );
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document.write( "x+y=31................(1)\r<BR>\n" );
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document.write( "25x+10y=520...........(2)\r<BR>\n" );
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document.write( "Multiply (1) by 10 and subtract (2)\r<BR>\n" );
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document.write( "10x+10y=310<BR>\n" );
document.write( "25x+10y=520\r<BR>\n" );
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document.write( "-15x=-210\r<BR>\n" );
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document.write( "x= 14\r<BR>\n" );
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document.write( "14 quarters and remaining dimes\r<BR>\n" );
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document.write( "25x+10y =  </SPAN>\n" );
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