document.write( "Question 982171: The dean of a university estimates that the mean number of classroom hours per week for full-time faculty is 10.0. As a member of the student council, you want to test this claim. A random sample of the number of classroom hours for 8 full-time faculty for one week is shown in the table below. At α=0.10 can you reject the dean's claim? Complete parts (a) through (c) below.
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document.write( "Assume the population is normally distributed.
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document.write( "10.3,8.2,11.3,6.5,4.9,9.6,14.1,8.8 \r
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document.write( "A. write the claim mathematically
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document.write( "B. What is the P value?
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document.write( "C. Decide whether to reject or fail to reject the null hypothesis. \n" );
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Algebra.Com's Answer #603028 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! A) The claim is mu = 10.0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The claim is the null hypothesis. The alternate hypothesis is mu =/= 10.0, so we have a two tailed test.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-----------------------------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "B)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Use a calculator to find that \n" ); document.write( "xbar = 9.2125 \n" ); document.write( "s = 2.84677\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now compute the test statistic:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "t = (xbar - mu)/(s/sqrt(n)) \n" ); document.write( "t = (9.2125- 10)/(2.84677/sqrt(8)) \n" ); document.write( "t = -0.78\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Use either a table or a calculator to find that P(T < -0.78) = 0.23047 (the degrees of freedom equals n-1 = 8-1 = 7)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The p-value is therefore 2*0.23047 = 0.46094\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-------------------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "C)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The p-value 0.46094 is larger than alpha = 0.10. So we fail to reject the null. We \"accept\" the claim that the mean mu is 10.0. We don't have enough evidence to overturn it. \n" ); document.write( " |