document.write( "Question 982117: The two vertices that form the non-congruent side of an isosceles triangle are (-5,3) and (2,3). What are the coordinates of the other vertex.\r
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document.write( "I am beyond lost. Thanks! \n" );
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Algebra.Com's Answer #602983 by macston(5194) You can put this solution on YOUR website! The other vertex that forms the triangle is on a line perpendicular to the segment at its midpoint. \n" ); document.write( ". \n" ); document.write( "Find the midpoint: \n" ); document.write( "midpoint=((x1+x2)/2,((y1+y2)/2) \n" ); document.write( "midpoint=((-5+2)/2,(3+3)/2) \n" ); document.write( "midpoint=(-(3/2),3) \n" ); document.write( ". \n" ); document.write( "Find the slope of the original segment: \n" ); document.write( "m=slope \n" ); document.write( "m=(y2-y1)/x2-x1 \n" ); document.write( "m=(3-3)/(2-(-5)=0/7=0 \n" ); document.write( "The line is horizontal. \n" ); document.write( ". \n" ); document.write( "The perpendicular line will be vertical, thus will have an undefined slope. \n" ); document.write( ". \n" ); document.write( "Equation for original line: \n" ); document.write( "y=mx+b \n" ); document.write( "y=3 \n" ); document.write( ". \n" ); document.write( "The vertical line through the midpoint is x=-(3/2)\r \n" ); document.write( "\n" ); document.write( "Any point on the line x=-(3/2) except (-(3/2),3) can be connected to the given vertices to form an isosceles triangle. \n" ); document.write( " \n" ); document.write( " |