document.write( "Question 982054: In the right triangle, triangle ABC, the altitude line segment CD is at a right angle to the hypotenuse. You can use \"+CD=sqrt%28%28+AD+%29%28+DB+%29%29+\" to find certain lengths.\r
\n" ); document.write( "\n" ); document.write( "a) find AD if CD=10 and DB=4\r
\n" ); document.write( "\n" ); document.write( "\"+CD=sqrt%28%28+AD+%29%28+DB+%29%29+\"
\n" ); document.write( "\"+10=sqrt%28%28+AD+%29%28+4+%29%29+\"
\n" ); document.write( "\"+10=sqrt%28+4AD+%29+\"
\n" ); document.write( "\"+10%5E2=%28sqrt%28+4AD+%29%29%5E2+\"
\n" ); document.write( "\"+100=4AD+\"
\n" ); document.write( "\"+100%2F4=%28+4AD+%29%2F4+\"
\n" ); document.write( "\"+25+=+AD+\"\r
\n" ); document.write( "\n" ); document.write( "b) find DB if AD=20 and CD=15\r
\n" ); document.write( "\n" ); document.write( "\"+CD=sqrt%28%28+AD+%29%28+DB+%29%29+\"
\n" ); document.write( "\"+15=sqrt%28%28+20+%29%28+DB+%29%29+\"
\n" ); document.write( "\"+15=sqrt%28+20DB+%29+\"
\n" ); document.write( "\"+15%5E2=%28sqrt%28+20DB+%29%29%5E2+\"
\n" ); document.write( "\"+225=20DB+\"
\n" ); document.write( "\"+225%2F20=%28+20DB+%29%2F20+\"
\n" ); document.write( "\"+45%2F4+=+DB+\" or 11.25\r
\n" ); document.write( "\n" ); document.write( " are my answers correct?\r
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Algebra.Com's Answer #602937 by Edwin McCravy(20055)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "One way to check them is with graph paper, pencil and ruler, and count the\r\n" );
document.write( "squares.  In the first one below, by counting the little squares on the\r\n" );
document.write( "graph paper, you see that AD=25,CD=10,DB=4. And if you put the corner of\r\n" );
document.write( "a sheet of paper at C, you will see that it is a right angle of 90°.\r\n" );
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document.write( "It appears that you have done good work, and neatly too, using the\r\n" );
document.write( "notation of this site.\r\n" );
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document.write( "Edwin
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